Milwaukee Bucks and Oklahoma City Thunder in NBA Cup finals

LAS VEGAS (USA) (ITALPRESS) – It will be Milwaukee and Oklahoma City playing for the NBA Cup. The Bucks and Thunder overcame Atlanta andHouston in Las Vegas, earning the right to play in the last act of the tournament in the night between Tuesday and Wednesday. In the first semifinal, it was Giannis Antetokounmpo who once again dragged Milwaukee to a 110-102 victory: the best scorer in the Nba this season (32.7 points average amatch), the Greek ace put up the fifth match in a row with at least 30 points. 32 in this circumstance against the Hawks, topped by 14 rebounds and 9 assists. In Atlanta, Trae Young’s 35 points, 10 assists and 7 rebounds were not enough.Milwaukee will then challenge Oklahoma, which at the T-Mobile Arena once again found in Shai Gilgeous-Alexander its ace: 32 points(plus 8 rebounds and six assists) against the Rockets, who were in fact in the game only for half of the contest and defeated 111-96. Gilgeous-Alexander found valuable allies in Isaiah Hartenstein (21 points), JalenWilliams (20) and Luguentz Dort (19).

– Photo Ipa Agency -(ITALPRESS).